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(F)=-14F^2+1260F-19600
We move all terms to the left:
(F)-(-14F^2+1260F-19600)=0
We get rid of parentheses
14F^2-1260F+F+19600=0
We add all the numbers together, and all the variables
14F^2-1259F+19600=0
a = 14; b = -1259; c = +19600;
Δ = b2-4ac
Δ = -12592-4·14·19600
Δ = 487481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1259)-\sqrt{487481}}{2*14}=\frac{1259-\sqrt{487481}}{28} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1259)+\sqrt{487481}}{2*14}=\frac{1259+\sqrt{487481}}{28} $
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